Java Character isSpace() 方法

2024 年 11 月 6 日 | 阅读 2 分钟

Character 类的 isSpace(char ch) 方法用于确定给定的（或指定的）字符是否为 ISO-LATIN-1 空白字符。

给定方法对于以下五个字符返回 true：

'\t' U+0009 水平制表符
'\n' U+000A 换行符
'\f' U+000C 换页符
'\r' U+000D 回车符
' ' U+0020 空格

语法

参数

ch：需要测试的字符。

返回值

isSpace(char ch) 方法返回一个布尔值，即如果给定的（或指定的）字符是 ISO-LATIN-1 空白字符，则返回 true。否则，该方法返回 false。

示例 1

public class JavaCharacterIsSapceExample1 {
  public static void main(String args[])
  {
      //Create three char primitives.
       char ch1 = '\n';
       char ch2 = '\t';
       char ch3 = ' ';
     //Create three boolean primitives.
       boolean b1 = Character.isSpace(ch1);
       boolean b2 = Character.isSpace(ch2);
        boolean b3 = Character.isSpace(ch3);
     // Print the result.
      System.out.println("The first character is a space character: " + b1);     
      System.out.println("The second character is a space character: " + b2);     
      System.out.println("The third character is a space character: " + b3);     
     }
}

输出

The first character is a space character: true
The second character is a space character: true
The third character is a space character: true

示例 2

public class JavaCharacterIsSapceExample2 {
      public static void main(String args[])
  {
      //Create two char primitives.
       char ch1 = '\f';
       char ch2 = '\r';
  
     //Create two boolean primitives.
       boolean b1 = Character.isSpace(ch1);
       boolean b2 = Character.isSpace(ch2);
     // Print the result.
      System.out.println("The first character is a space character: " + b1);     
      System.out.println("The second character is a space character: " + b2);    
     }
}

输出

The first character is a space character: true
The second character is a space character: true

下一主题Java-character-isspacechar-method

Java Character isSpace() 方法

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Java Character isSpace() 方法

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返回值

示例 1

示例 2

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