Java Double longBitsToDouble() 方法

2024 年 11 月 10 日 | 阅读 2 分钟

Java Double 类的 longBitsToDouble() 方法返回一个表示给定位表示的 double 值。

结果为

如果传入的参数为 0x7ff0000000000000L，则为正无穷大。
如果传入的参数为 0x7ff0000000000000L，则为负无穷大。

语法

参数

bits - 是传入的 long 整数。

返回值

longBitsToDouble() 方法返回一个具有相同位模式的 double 类型浮点值。

示例 1

public class Double_longBitsToDoubleMethodExample1 {
    public static void main(String[] args) {

             int value1=76767127;

             Double d1=Double.longBitsToDouble(value1);
             System.out.println("Float value after conversion = "+d1);

             int value2=48667;
             //method can be called directly in println function
             System.out.println("Float value after conversion = "+Double.longBitsToDouble(value2));

             //passing negative integer
             int value3=-4756;
        System.out.println("Float value after conversion = "+Double.longBitsToDouble(value3));


    }
}

输出

Float value after conversion = 3.7928E-316
Float value after conversion = 2.40447E-319
Float value after conversion = NaN

示例 2

public class Double_longBitsToDoubleMethodExample2 {

    public static void main(String[] args) {

      //result returned is positive infinity

       int value1=  0X7f800000;

        System.out.println("1. "+value1+ " value = "+Double.longBitsToDouble(value1));

        // result returned is negative infinity

        int value2=0Xff800000;

        System.out.println("2. "+value1+ " value = "+Double.longBitsToDouble(value2));

        int value3 =Integer.MAX_VALUE;

        System.out.println("3. "+value3 + " value = " +Double.longBitsToDouble(value3));

        int value4 =Integer.MIN_VALUE;

        System.out.println("4. "+ value4 + " value = " +Double.longBitsToDouble(value4));

}

}

输出

1. 2139095040 value = 1.0568533725E-314
2. 2139095040 value = NaN
3. 2147483647 value = 1.060997895E-314
4. -2147483648 value = NaN

示例 3

import java.util.Scanner;

public class Double_longBitsToDoubleMethodExample3 {

    public static void main(String[] args) {

        Scanner scanner = new Scanner(System.in);

        System.out.println("Enter first integer:");

        int value1=scanner.nextInt();

        System.out.println("1. Double value = "+Double.longBitsToDouble(value1));

        System.out.println("\nEnter Second negative integer");

        int value2=scanner.nextInt();

        if(value2<0) {

            System.out.println("2. Double value = " + Double.longBitsToDouble(value2));

        }

        else{

            System.err.println("plz re enter negative integer.");

        }

    }

}

输出

Enter first integer:
648375
1. Double value = 3.2034E-318

Enter Second negative integer
-48755
2. Double value = NaN

下一主题Java-double-longvalue-method

Java Double longBitsToDouble() 方法

语法

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示例 1

示例 2

示例 3

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Java Double longBitsToDouble() 方法

语法

参数

返回值

示例 1

示例 2

示例 3

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