Java Integer reverse() 方法

2025 年 3 月 25 日 | 阅读 2 分钟

Java Integer 类的 reverse() 方法在数值上返回通过反转指定整数值的二进制补码表示形式的位顺序而获得的值。

语法

以下是 reverse() 方法的声明

参数

数据类型	参数	描述	必需/可选
int	i	要反转其位的整数值。	必需

返回值

reverse() 方法返回通过反转指定 int 值的位顺序而获得的数值。

异常

不适用

兼容版本

Java 1.5 及以上版本

示例 1

public class IntegerReverseExample1 {
	public static void main(String[] args) {
	      int i = 202;
	      System.out.println("Number = " + i);
	      //returns the value obtained by reversing order of the bits in the specified int value
	      System.out.println("After reversing = " + Integer.reverse(i));
    }
}

输出

Number = 202
After reversing = 1392508928

示例 2

import java.util.Scanner;
public class IntegerReverseExample2 {
	public static void main(String[] args) {
	    System.out.print("Enter Integer Value: ");
	    Scanner readInput = new Scanner(System.in);
	    int i = readInput.nextInt();
	    readInput.close();
	    System.out.println("Number = " + i);
	    // returns the integer value in binary	         
	    System.out.println("Binary Representation = " + Integer.toBinaryString(i));
	    //returns the value obtained by reversing order of the bits in the specified int value
	    System.out.println("After reversing = " + Integer.reverse(i));
    }
}

输出

Enter Integer Value: 140
Number = 140
Binary Representation = 10001100
After reversing = 822083584

示例 3

public class IntegerReverseExample3 {
	public static void main(String[] args) {
	      int a = 202;
	      int b = -50;
	      System.out.println("Number = " + a);	         
	      System.out.println("Binary Representation = " + Integer.toBinaryString(a));	      
	      System.out.println("After reversing = " + Integer.reverse(a));
	      System.out.println("\nNumber = " + b);	         
	      System.out.println("Binary Representation = " + Integer.toBinaryString(b));	      
	      System.out.println("After reversing = " + Integer.reverse(b));
    }
}

输出

Number = 202
Binary Representation = 11001010
After reversing = 1392508928

Number = -50
Binary Representation = 11111111111111111111111111001110
After reversing = 1946157055

示例 4

import java.util.Scanner;
public class LongReverseExample4 {
	public static void main(String[] args) {
		System.out.print("Enter Number from console: ");
		Scanner sc = new Scanner(System.in);
		// assign the input to a variable
		long value = sc.nextLong();
		// get the value by reversing the order of the bytes 
		long result = Long.reverse(value);
		// print the result
		System.out.println("Result: " + result);
		sc.close();
	}
}

输出

Enter Number from console: 3456546
Result: 4935149145179553792

下一主题Java-integer-rotateleft-method

Java Integer reverse() 方法

语法

参数

返回值

异常

兼容版本

示例 1

示例 2

示例 3

示例 4

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Java Integer reverse() 方法

语法

参数

返回值

异常

兼容版本

示例 1

示例 2

示例 3

示例 4

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