Java LinkedBlockingDeque peekLast() 方法

2025 年 3 月 21 日 | 阅读 2 分钟

LinkedBlockingDeque 类的 peekLast() 方法检索此双端队列的最后一个元素，但不会将其移除。如果此双端队列为空，则该方法返回 null。

语法

参数

不适用

指定者：

LinkedBlockingDeque 类的 peekLast () 方法由 Deque<E> 接口中的 peekLast() 方法指定。

返回值

peekLast () 方法返回此双端队列的尾部元素，如果此双端队列为空，则返回 null。

示例 1

import java.util.concurrent.LinkedBlockingDeque;
public class LinkedBlockingDequePeekLastExample1 {
    public static void main(String[] args) {
        int capacity =20;
        LinkedBlockingDeque<Integer> deque = new LinkedBlockingDeque<Integer>(capacity);

        deque.add(412);
        deque.add(556);
        deque.add(654);
        deque.add(732);
        deque.add(879);
        deque.add(943);
            
        System.out.println("Last element of deque  : "+deque.peekLast());
        System.out.println("Deque after peekLast() : "+deque);
    }
}

输出

Last element of deque  : 943
Deque after peekLast() : [412, 556, 654, 732, 879, 943]

示例 2

import java.util.concurrent.LinkedBlockingDeque;
public class LinkedBlockingDequePeekLastExample2 {
    public static void main(String[] args) {
        int capacity =20;
        LinkedBlockingDeque<String> deque1 = new LinkedBlockingDeque<String>(capacity);
        LinkedBlockingDeque<String> deque2 = new LinkedBlockingDeque<String>(capacity);
        
        deque1.add("Keshav");
        deque1.add("Naveen");
        deque1.add("Neha");
        deque1.add("Hitesh");
        deque1.add("Surbhi");
        deque1.add("Nitin");

        deque2.add("Ankit");
        deque2.add("Megha");
        deque2.add("Janak");
        deque2.add("Riya");    
        
        System.out.println("Last element of deque1  : "+deque1.peekLast());
        System.out.println("Deque1 after peekLast() : "+deque1 +"\n" );
        
        System.out.println("Last element of deque2  : "+deque2.peekLast());
        System.out.println("Deque2 after peekLast() : "+deque2);
    }
}

输出

Last element of deque1  : Nitin
Deque1 after peekLast() : [Keshav, Naveen, Neha, Hitesh, Surbhi, Nitin]

Last element of deque2  : Riya
Deque2 after peekLast() : [Ankit, Megha, Janak, Riya]

示例 3

import java.util.concurrent.LinkedBlockingDeque;
public class LinkedBlockingDequePeekLastExample3 {
    public static void main(String[] args) {
        int capacity =20;
        LinkedBlockingDeque<String> deque = new LinkedBlockingDeque<String>(capacity);
        
        deque.add("Employee1");
        deque.add("Employee2");
        deque.add("Employee3");
        deque.add("Employee4");
        deque.clear();
                
        System.out.println("Last element of deque  : "+deque.peekLast());
        System.out.println("Deque after peekLast() : "+deque +"\n" );
    }
}

输出

Last element of deque  : null
Deque after peekLast() : []

下一主题Java Linkedblockingdeque

Java LinkedBlockingDeque peekLast() 方法

语法

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示例 1

示例 2

示例 3

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Java LinkedBlockingDeque peekLast() 方法

语法

参数

指定者：

返回值

示例 1

示例 2

示例 3

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