Java LinkedTransferQueue iterator() 方法

2025 年 3 月 21 日 | 阅读 2 分钟

LinkedTransferQueue 类的 iterator() 方法用于返回此队列中元素的迭代器，按正确顺序排列。

语法

指定者：

LinkedTransferQueue 类的 iterator() 方法由以下接口指定：

接口 Iterable<E> 中的 iterator
接口 Collection<E> 中的 iterator
类 AbstractCollection<E> 中的 iterator

此方法返回此队列中元素的迭代器，按正确顺序排列。

示例 1

import java.util.Iterator;
import java.util.concurrent.LinkedTransferQueue;
public class LinkedTransferQueueIteratorExample1 {
static int i = 1;
public static void main(String[] args) {
LinkedTransferQueue<String> queue = new LinkedTransferQueue<String>();
queue.add("Jackson");
queue.add("Harry");
queue.add("John");
queue.add("Honey");
        Iterator<String> iterator = queue.iterator();
//Returns an iterator over the elements
while (iterator.hasNext()) {
System.out.println(i++ + "." + iterator.next());
        }
    }
}

输出

1.Jackson
2.Harry
3.John
4.Honey

示例 2

import java.util.Iterator;
import java.util.concurrent.LinkedTransferQueue;
class Student {
static int i = 1;
public String name;
public String college;
    String rollNo;
    Student(String rollNo, String college, String name) {
this.rollNo= rollNo;
this.name = name;
this.college= college;
    }
public String toString() {
return i++ + ".Roll No. =  " + this.rollNo+ "\n  College =  " + this.college+ "\n  Name = " + this.name + "\n";
    }
}
public class LinkedTransferQueueIteratorExample2 {
static int i=1;
public static void main(String[] args) {
	Student student1 = new Student("15cs1029", "AKTU University", "Harry");
	Student student2 = new Student("15cs1010", "CCS University", "Johnson");
	Student student3 = new Student("17cs1029", "MR University", "Marry");
	Student student4 = new Student("15cs1011", "MVN University", "Jack");
	LinkedTransferQueue<Student> queue = new LinkedTransferQueue<Student>();
queue.add(student1);
queue.add(student2);
queue.add(student3);
queue.add(student4);
        Iterator<Student> iterator = queue.iterator();
//Returns an iterator over the elements
while (iterator.hasNext()) {
System.out.println(i++ + "." + iterator.next());
        }
    }
}

输出

1.1.Roll No. =  15cs1029
  College =  AKTU University
  Name = Harry

2.2.Roll No. =  15cs1010
  College =  CCS University
  Name = Johnson

3.3.Roll No. =  17cs1029
  College =  MR University
  Name = Marry

4.4.Roll No. =  15cs1011
  College =  MVN University
  Name = Jack

示例 3

import java.util.Collections;
import java.util.Iterator;
import java.util.concurrent.ConcurrentLinkedQueue;
import java.util.concurrent.LinkedTransferQueue;
public class LinkedTransferQueueIteratorExample3 {
public static void main(String[] args) {
	Integer[] val = {0, 1};
	LinkedTransferQueue<Integer> queue = new LinkedTransferQueue<Integer>();
queue.add(71018);
queue.add(8000);
queue.add(1178);
queue.add(1190);
//Returns an iterator over the elements
Iterator<Integer> iterator = queue.iterator();
while(iterator.hasNext()){
System.out.println(iterator.next());
val[0] = Collections.max(queue);
val[1] = Collections.min(queue);
        }
System.out.println("Max number = "+ val[0]);
System.out.println("Min number = "+ val[1]);
    }
}

输出

71018
8000
1178
1190
Max number = 71018
Min number = 1178

下一主题Java LinkedTransferQueue

Java LinkedTransferQueue iterator() 方法

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Java LinkedTransferQueue iterator() 方法

语法

指定者：

返回

示例 1

示例 2

示例 3

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