问. 打印偶数位置数组元素的程序。

2025年3月17日 | 阅读 3 分钟

说明

在此程序中，我们需要打印位于偶数位置的元素。

通过遍历数组并将 i 的值增加 2 来找到偶数位置的元素。

Program to print the elements of an array present on even position

在上面的数组中，位于偶数位置的元素是 b 和 d。

算法

声明并初始化一个数组。
计算已声明数组的长度。
通过将变量“i”的值初始化为 1（因为第一个偶数位置的元素位于 i = 1）来循环遍历数组，然后将其值增加 2，即 i=i+2。
打印位于偶数位置的元素。

解决方案

Python

#Initialize array 
arr = [1, 2, 3, 4, 5]; 
 
print("Elements of given array present on even position: ");
#Loop through the array by incrementing the value of i by 2

#Here, i will start from 1 as first even positioned element is present at position 1.
for i in range(1, len(arr), 2):
    print(arr[i]); 

输出

Elements of given array present on even position: 
2
4

C

#include <stdio.h>
 
int main()
{
    //Initialize array 
    int arr[] = {1, 2, 3, 4, 5}; 
        //Calculate length of array arr
    int length = sizeof(arr)/sizeof(arr[0]);
    printf("Elements of given array present on even position: \n");
    //Loop through the array by incrementing value of i by 2
    //Here, i will start from 1 as first even positioned element is present at position 1.
    for (int i = 1; i < length; i = i+2) { 
        printf("%d\n", arr[i]); 
    } 
    return 0;
}

输出

Elements of given array present on even position: 
2
4

JAVA

public class EvenPosition {
    public static void main(String[] args) {
        
        //Initialize array 
        int [] arr = new int [] {1, 2, 3, 4, 5}; 
        
        System.out.println("Elements of given array present on even position: ");
        //Loop through the array by incrementing value of i by 2
        //Here, i will start from 1 as first even positioned element is present at position 1.
        for (int i = 1; i < arr.length; i = i+2) { 
            System.out.println(arr[i]); 
        }  
    }
}

输出

Elements of given array present on even position: 
2
4

C#

using System;
public class EvenPosition
{
    public static void Main()
    {
        //Initialize array 
        int [] arr = new int [] {1, 2, 3, 4, 5}; 
        
        Console.WriteLine("Elements of given array present on even position: ");
        //Loop through the array by incrementing value of i by 2
        //Here, i will start from 1 as first even positioned element is present at position 1.
        for (int i = 1; i < arr.Length; i = i+2) { 
            Console.WriteLine(arr[i]); 
        }  
    }
}

输出

Elements of given array present on even position: 
2
4

PHP

<!DOCTYPE html>
<html>
<body>
<?php
//Initialize array 
$arr = array(1, 2, 3, 4, 5); 
 
print("Elements of given array present on even position: <br>");
//Loop through the array by incrementing value of i by 2
//Here, i will start from 1 as first even positioned element is present at position 1.
for ($i = 1; $i < count($arr); $i = $i+2) { 
    print($arr[$i] . "<br>"); 
}  
?>
</body>
</html> 

输出

Elements of given array present on even position: 
2
4

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问. 打印偶数位置数组元素的程序。

说明

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Python

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JAVA

C#

PHP

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程序

问. 打印偶数位置数组元素的程序。

说明

算法

解决方案

Python

C

JAVA

C#

PHP

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