C 语言员工记录系统

2024 年 8 月 28 日 | 阅读 9 分钟

员工记录系统是一款旨在处理企业主要行政任务的软件。通过ERS，企业可以跟踪每一位员工及其数据。它被用于使用电子系统管理企业。该程序旨在管理任何企业的人事记录。将所有人事记录集中存放将有助于企业。

员工记录系统的目的是：用户将有5个选择

创建新记录。
删除记录。
修改记录。
查看所有记录。
退出。

员工信息

姓名。
年龄。
薪水。
员工ID。

程序方法

应用程序名称和创建者显示在第一个框架中：它由几个printf命令和一个系统提供的函数()创建。标准C/C++库中包含system()函数。它用于传输操作系统命令处理器或终端可以执行的命令，然后在命令完成后返回。System("Color 3F") 将改变控制台背景颜色 (3) 以及控制台上的前景色文本 (F)。System("pause") 将暂停屏幕，用户将收到一条消息：按任意键继续。gotoxy() 方法将有助于设置显示数据的坐标。

程序分解

struct emp {
	char name [ 50 ] ;
	float salary ;
	int age ;
	int id ;
} ;

以上代码将用于创建员工结构。

void gotoxy ( int x , int y )
{
	cord.X = x ;
	cord.Y = y ;
	SetConsoleCursorPosition (
		GetStdHandle ( STD_OUTPUT_HANDLE ) ,
		cord ) ;
}

FILE * fp , * ft ;

以上代码将设置控制台光标位置。

void addrecord ( )
{
	system ( " cls " ) ;
	fseek ( fp , 0 , SEEK_END ) ;
	char another = ' y ' ;

	while ( another = = ' y ' ) {
		printf ( " \ n Enter Name : " ) ;
		scanf ( " % s " , e.name ) ;

		printf ( " \ nEnter Age : " ) ;
		scanf ( " % d " , & e.age ) ;

		printf ( " \ n Enter Salary : " ) ;
		scanf ( " % f " , & e.salary ) ;

		printf ( " \ n Enter EMP-ID : " ) ;
		scanf ( " % d " , & e.id ) ;

		fwrite ( & e , size , 1 , fp ) ;

		printf ( " \ n Want to add another "
			" record ( Y / N ) : " ) ;
		fflush ( stdin ) ;

		scanf ( " % c " , & another ) ;
	}
}

以上代码将用于添加记录。

void deleterecord ( )
{
	system ( " cls " ) ;
	char empname [ 50 ] ;
	char another = ' y ' ;

	while ( another = = ' y  ' ) {
		printf ( " \ n Enter employee "
			" name to delete : " ) ;
		scanf ( " % s " , empname ) ;

		ft = fopen ( " temp.txt " , " wb " ) ;
		rewind ( fp ) ;

		while ( fread ( & e , size ,
					1 , fp )
			= = 1 ) {
			if ( strcmp ( e.name ,
					empname )
				! = 0 )
				fwrite ( & e , size , 1 , ft ) ;
		}

		fclose ( fp ) ;
		fclose ( ft ) ;
		remove ( " data.txt " ) ; 
		rename ( " temp.txt " , " data.txt " ) ;
		fp = fopen ( " data.txt " , " rb + " ) ;

		printf ( " \ n Want to delete another "
			" record ( Y / N ) : " ) ;
		fflush ( stdin ) ;
		another = getche ( ) ;
	}
}

以上代码用于从系统中删除记录。

void displayrecord ( )
{
	system ( " cls " ) ;

	// sets pointer to start
	// of the file
	rewind ( fp ) ;

	printf ( " \ n = = = = = = = = = = = = = = = = = = = = = = = = = "
		" = = = = = = = = = = = = = = = = = = = = = = = = = = = "
		" = = = = = = " ) ;
	printf ( " \ n NAME \ t \ t AGE \ t \ t SALARY\ t \ t "
		 " \ t I D \ n " ,
		e.name , e.age ,
		e.salary , e.id ) ;
	printf ( " = = = = = = = = = = = = = = = = = = = = = = = = = = = "
		" = = = = = = = = = = = = = = = = = = = = = = = = = = = "
		" = = = = \ n " ) ;
	while ( fread ( & e , size , 1 , fp ) = = 1 )
		printf ( " \ n % s \ t \ t % d \ t \ t%.2f \ t % 10d " ,
			e.name , e.age , e.salary , e.id ) ;

	printf ( " \ n \ n \ n \ t " ) ;
	system ( " pause " ) ;
}

以上代码将用于显示记录。

void modifyrecord ( )
{
	system ( " cls " ) ;
	char empname [ 50 ] ;
	char another = ' y ' ;

	while ( another = = ' y ' ) {
		printf ( " \ n Enter employee name "
			" to modify : " ) ;
		scanf ( " % s " , empname ) ;

		rewind ( fp ) ;

		// While File is open
		while ( fread ( & e , size , 1 , fp ) = = 1 ) {
			// Compare the employee name
			// with ename
			if ( strcmp ( e.name , empname ) = = 0 ) {
				printf ( " \ n Enter new name : " ) ;
				scanf ( " % s " , e.name ) ;
				printf ( " \ n Enter new age : " ) ;
				scanf ( " % d " , & e.age ) ;
				printf ( " \ n Enter new salary : " ) ;
				scanf ( " % f " , & e.salary ) ;
				printf ( " \ n Enter new EMP-ID : " ) ;
				scanf ( " % d " , & e.id ) ;

				fseek ( fp , -size , SEEK_CUR ) ;
				fwrite ( & e , size , 1 , fp ) ;
				break ;
			}
		}

		// Ask for modifying another record
		printf ( " \ n Want to modify another "
			" record ( Y / N ) : " ) ;
		fflush ( stdin ) ;
		scanf ( " % c " , & another ) ;
	}
}

以上代码将用于修改系统中的现有记录。

C语言员工记录系统程序

// C program for the above approach
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <windows.h>

// Structure of the employee
struct emp {
	char name[50];
	float salary;
	int age;
	int id;
};
struct emp e;

// size of the structure
long int size = sizeof(e);

// In the start coordinates
// will be 0, 0
COORD cord = { 0, 0 };

// function to set the
// coordinates
void gotoxy(int x, int y)
{
	cord.X = x;
	cord.Y = y;
	SetConsoleCursorPosition(
		GetStdHandle(STD_OUTPUT_HANDLE),
		cord);
}

FILE *fp, *ft;

// Function to add the records
void addrecord()
{
	system("cls");
	fseek(fp, 0, SEEK_END);
	char another = 'y';

	while (another == 'y') {
		printf("\nEnter Name : ");
		scanf("%s", e.name);

		printf("\nEnter Age : ");
		scanf("%d", &e.age);

		printf("\nEnter Salary : ");
		scanf("%f", &e.salary);

		printf("\nEnter EMP-ID : ");
		scanf("%d", &e.id);

		fwrite(&e, size, 1, fp);

		printf("\nWant to add another"
			" record (Y/N) : ");
		fflush(stdin);

		scanf("%c", &another);
	}
}

// Function to delete the records
void deleterecord()
{
	system("cls");
	char empname[50];
	char another = 'y';

	while (another == 'y') {
		printf("\nEnter employee "
			"name to delete : ");
		scanf("%s", empname);

		ft = fopen("temp.txt", "wb");
		rewind(fp);

		while (fread(&e, size,
					1, fp)
			== 1) {
			if (strcmp(e.name,
					empname)
				!= 0)
				fwrite(&e, size, 1, ft);
		}

		fclose(fp);
		fclose(ft);
		remove("data.txt");
		rename("temp.txt", "data.txt");
		fp = fopen("data.txt", "rb+");

		printf("\nWant to delete another"
			" record (Y/N) :");
		fflush(stdin);
		another = getche();
	}
}

// Function to display the record
void displayrecord()
{
	system("cls");

	// sets pointer to start
	// of the file
	rewind(fp);

	printf("\n= = = = = = = = = = = = = = = = = = = = = = = = ="
		"= = = = = = = = = = = = = = = = = = = = = = = = = = ="
		"= = = = = =");
	printf("\nNAME\t\tAGE\t\tSALARY\t\t"
		"\tID\n",
		e.name, e.age,
		e.salary, e.id);
	printf("= = = = = = = = = = = = = = = = = = = = = = = = = = ="
		"= = = = = = = = = = = = = = = = = = = = = = = = = = ="
		"= = = =\n");
	while (fread(&e, size, 1, fp) == 1)
		printf("\n%s\t\t%d\t\t%.2f\t%10d",
			e.name, e.age, e.salary, e.id);

	printf("\n\n\n\t");
	system("pause");
}

// Function to modify the record
void modifyrecord()
{
	system("cls");
	char empname[50];
	char another = 'y';

	while (another == 'y') {
		printf("\nEnter employee name"
			" to modify : ");
		scanf("%s", empname);

		rewind(fp);

		// While File is open
		while (fread(&e, size, 1, fp) == 1) {
			// Compare the employee name
			// with ename
			if (strcmp(e.name, empname) == 0) {
				printf("\nEnter new name:");
				scanf("%s", e.name);
				printf("\nEnter new age :");
				scanf("%d", &e.age);
				printf("\nEnter new salary :");
				scanf("%f", &e.salary);
				printf("\nEnter new EMP-ID :");
				scanf("%d", &e.id);

				fseek(fp, -size, SEEK_CUR);
				fwrite(&e, size, 1, fp);
				break;
			}
		}

		// Ask for modifying another record
		printf("\nWant to modify another"
			" record (Y/N) :");
		fflush(stdin);
		scanf("%c", &another);
	}
}

// Driver code
int main()
{
	int choice;

	// opening the file
	fp = fopen("data.txt", "rb+");

	// showing error if file is
	// unable to open.
	if (fp == NULL) {
		fp = fopen("data.txt", "wb+");
		if (fp == NULL) {
			printf("\nCannot open file...");
			exit(1);
		}
	}

	system("Color 3F");
	printf("\n\n\n\n\t\t\t\t============="
		"============================="
		"===========");
	printf("\n\t\t\t\t~~~~~~~~~~~~~~~~~~~"
		"~~~~~~~~~~~~~~~~~~~~~~~~~~~~~"
		"~~~~~");
	printf("\n\t\t\t\t==================="
		"============================="
		"=====");
	printf("\n\t\t\t\t[|:::>:::>:::>::> "
		"EMPLOYEE RECORD <::<:::<:::"
		"<:::|]\t");
	printf("\n\t\t\t\t==================="
		"============================="
		"=====");
	printf("\n\t\t\t\t~~~~~~~~~~~~~~~~~~~~"
		"~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~"
		"~~~");
	printf("\n\t\t\t\t====================="
		"==============================\n");
	system("pause");

	while (1) {
		// Clearing console and asking the
		// user for input
		system("cls");
		gotoxy(30, 10);
		printf("\n1. ADD RECORD\n");
		gotoxy(30, 12);
		printf("\n2. DELETE RECORD\n");
		gotoxy(30, 14);
		printf("\n3. DISPLAY RECORDS\n");
		gotoxy(30, 16);
		printf("\n4. MODIFY RECORD\n");
		gotoxy(30, 18);
		printf("\n5. EXIT\n");
		gotoxy(30, 20);
		printf("\nENTER YOUR CHOICE...\n");
		fflush(stdin);
		scanf("%d", &choice);

		// Switch Case
		switch (choice) {
		case 1:

			// Add the records
			addrecord();
			break;

		case 2:

			// Delete the records
			deleterecord();
			break;

		case 3:

			// Display the records
			displayrecord();
			break;

		case 4:

			// Modify the records
			modifyrecord();
			break;

		case 5:
			fclose(fp);
			exit(0);
			break;

		default:
			printf("\nINVALID CHOICE...\n");
		}
	}

	return 0;
}

输出

         = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = 
         ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
         = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = =
         [|:::>:::>:::>::> EMPLOYEE RECORD <::<:::<:::<:::|]       
         =====================================================     
         ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~     
         ===================================================
1. ADD RECORD

2. DELETE RECORD
                                                                                                
3. DISPLAY RECORDS                                                                              
                                                                                                
4. MODIFY RECORD                                                                                
                                                                                                
5. EXIT                                                                                         
                                                                                                
ENTER YOUR CHOICE...
1
Enter Name : Ravi

Enter Age : 26

Enter Salary : 120000

Enter EMP-ID : [email protected]

Want to add another record (Y/N) : Y
Enter Name : Shreya

Enter Age : 24

Enter Salary : 120000 

Enter EMP-ID : [email protected]

Want to add another record (Y/N) : N  
1. ADD RECORD

2. DELETE RECORD
                                                                                                
3. DISPLAY RECORDS                                                                              
                                                                                                
4. MODIFY RECORD                                                                                
                                                                                                
5. EXIT                                                                                         
                                                                                                
ENTER YOUR CHOICE...                                                                            
3
==========================================================
NAME            AGE             SALARY                  ID
==========================================================

Ravi            26              120000.00                0
Ravi            26              120000.00                0
Shreya          24              120000.00                0

        Press any key to continue . . .
Enter employee name to delete : Ravi

Want to delete another record (Y/N) : N
4
Enter employee name to modify : Ravi

Enter new name:Ravi

Enter new age :25

Enter new salary :125000

Enter new EMP-ID: [email protected]

Enter employee name to delete : Ravi

Want to delete another record (Y/N) :Y
Enter employee name to delete : Ravi

Want to delete another record (Y/N) : N

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