8 年级数学第 2 章:一元线性方程 的 NCERT 解决方案2024 年 9 月 24 日 | 阅读 8 分钟 练习 2.1求解下列方程并检验结果。 1. 3x = 2x + 18 答案: x = 18 解释: 3x = 2x + 18 两边同时减去 2x, 3x - 2x = 2x + 18 - 2x 3x - 2x = 2x- 2x + 18 x = 0 + 18 x = 18 2. 5t - 3 = 3t - 5 答案: t = - 1 解释: 5t - 3 = 3t - 5 将 3t 移项到等号左边(LHS), 5t - 3 - 3t = - 5 5t - 3t - 3 = - 5 2t - 3 = - 5 将 (- 3) 移项到等号右边(RHS), 2t = - 5 + 3 2t = - 2 两边同时除以 2, 2t/2 = - 2/2 t = - 1 注意:移项时,数字的符号会改变。3. 5x + 9 = 5 + 3x 答案: x = -2 解释: 5x + 9 = 5 + 3x 将 3x 移项到等号左边(LHS), 5x + 9 - 3x = 5 5x - 3x + 9 = 5 2x + 9 = 5 将 (9) 移项到等号右边(RHS), 2x = 5 - 9 2x = -4 两边同时除以 2, 2x/2 = -4/2 x = -2 4. 4z + 3 = 6 + 2z 答案: z = 3/2 解释: 4z + 3 = 6 + 2z 将 2z 移项到等号左边, 4z + 3 - 2z = 6 4z - 2z + 3 = 6 2z + 3 = 6 两边同时减去 3, 2z + 3 - 3 = 6 - 3 2z + 0 = 3 2z = 3 两边同时除以 2, 2z/2 = 3/2 z = 3/2 5. 2x - 1 = 14 - x 答案: x = 5 解释: 2x - 1 = 14 - x 将 - x 移项到等号左边, 2x - 1 + x = 14 2x + x - 1 = 14 3x - 1 = 14 两边同时加上 1, 3x - 1 + 1 = 14 + 1 3x + 0 = 15 3x = 15 两边同时除以 3, 3x/3 = 15/3 x = 5 6. 8x + 4 = 3 (x - 1) + 7 答案: x = 0 解释: 8x + 4 = 3 (x - 1) + 7 打开括号。 8x + 4 = 3x - 3 + 7 8x + 4 = 3x + 4 将 3x 移项到等号左边, 8x - 3x + 4 = 4 5x + 4 = 4 两边同时减去 4, 5x + 4 - 4 = 4 - 4 5x + 0 = 0 5x = 0 x = 0 7. x = 4/5 (x + 10) 答案: x = 40 解释: x = 4/5 (x + 10) 首先打开右边的括号。 x = 4x/5 + 4/5 × 10 x = 4x/5 + 8 将方程两边同时乘以 5, 5x = 5 × (4x/5 + 8) 5x = 4x + 40 将 4x 移项到等号左边, 5x - 4x = 40 x = 40 8. 2x/3 + 1 = 7x/15 + 3 答案: x = 10 解释: 2x/3 + 1 = 7x/15 + 3 将方程两边同时乘以 15, 15 × (2x/3 + 1) = 15 × (7x/15 + 3) 10x + 15 = 7x + 45 两边同时减去 15, 10x + 15 - 15 = 7x + 45 - 15 10x + 0 = 7x + 30 10x = 7x + 30 将 7x 移项到等号左边, 10x - 7x = 30 3x = 30 两边同时除以 3, 3x/3 = 30/3 x = 10 9. 2y + 5/3 = 26/3 − y 答案: y = 7/3 解释: 2y + 5/3 = 26/3 - y 将方程两边同时乘以 3, 3 × (2y + 5/3) = 3 × (26/3 - y) 6y + 5 = 26 - 3y 将 (- 3y) 移项到等号左边, 6y + 3y + 5 = 26 9y + 5 = 26 两边同时减去 5, 9y + 5 - 5 = 26 - 5 9y = 21 两边同时除以 9, 9y/9 = 21/9 y = 21/9 y = 7/3 10. 3m = 5 m - 8/5 答案: m = 4/5 解释: 3m = 5 m - 8/5 将 5m 移项到等号左边, 3m - 5m = - 8/5 - 2m = - 8/5 两边的负号可以抵消。 2m = 8/5 将方程两边同时乘以 5, 2m × 5 = 8/5 × 5 10m = 8 两边同时除以 10, 10m/10 = 8/10 m = 8/10 m = 4/5 通过将变量的值代入方程,我们可以检验 LHS 和 RHS。 练习 2.2求解下列线性方程. 1. x/2 - 1/5 = x/3 + 1/4 答案: x = 27/10 解释: 将方程两边同时乘以 60, 60 × (x/2 - 1/5) = 60 × (x/3 + 1/4) 30x - 12 = 20x + 15 将 20x 移项到等号左边, 30x - 20x - 12 = 15 10x - 12 = 15 两边同时加上 12, 10x - 12 + 12 = 15 + 12 10x + 0 = 27 10x = 27 两边同时除以 10, 10x/10 = 27/10 x = 27/10 2. n/2 - 3n/4 + 5n/6 = 21 答案: n = 36 解释: 将方程两边同时乘以 12, 12 × (n/2 - 3n/4 + 5n/6) = 12 × 21 6n - 9n + 10n = 252 7n = 252 两边同时除以 7, 7n/7 = 252/7 n = 36 3. x + 7 - 8x/3 = 17/6 - 5x/2 答案: x = - 5 解释: 将方程两边同时乘以 6, 6 × (x + 7 - 8x/3) = 6 × (17/6 - 5x/2) 6x + 42 - 16x = 17 - 15x 42 - 10x = 17 - 15x 将 (- 15x) 移项到等号左边, 42 - 10x + 15x = 17 42 + 5x = 17 两边同时减去 42, 42 + 5x - 42 = 17 - 42 5x + 0 = - 25 5x = - 25 两边同时除以 5, 5x/5 = - 25/5 x = - 5 4. (x - 5)/3 = (x - 3)/5 答案: x = 8 解释: 将方程两边同时乘以 15, 15 × ((x - 5)/3) = 15 × ((x - 3)/5) 5(x - 5) = 3 (x - 3) 打开括号, 5x - 25 = 3x - 9 将 3x 移项到等号左边, 5x - 3x - 25 = - 9 2x - 25 = - 9 两边同时加上 25, 2x - 25 + 25 = - 9 + 25 2x = 16 两边同时除以 2, 2x/2 = 16/2 x = 8 5. (3t - 2)/4 - (2t + 3)/3 = 2/3 - t 答案: t = 2 解释: 将方程两边同时乘以 12, 12 × ((3t - 2)/4 - (2t + 3)/3) = 12 × (2/3 - t) 3 (3t - 2) - 4 (2t + 3) = 8 - 12t 9t - 6 - 8t - 12 = 8 - 12t t - 18 = 8 - 12t 将 (- 12t) 移项到等号左边, t - 18 + 12t = 8 13t - 18 = 8 两边同时加上 18, 13t - 18 + 18 = 8 + 18 13t + 0 = 26 13t = 26 两边同时除以 13, 13t/13 = 26/13 t = 2 6. m - (m - 1)/2 = 1 - (m - 2)/3 答案: m = 7/5 解释: 将方程两边同时乘以 6, 6 × (m - (m - 1)/2) = 6 × (1 - (m - 2)/3) 6m - 3(m - 1) = 6 - 2(m - 2) 6m - 3m + 3 = 6 - 2m + 4 3m + 3 = 10 - 2m 将 (- 2m) 移项到等号右边(RHS), 3m + 3 + 2m = 10 5m + 3 = 10 两边同时减去 3, 5m + 3 - 3 = 10 - 3 5m + 0 = 7 5m = 7 两边同时除以 5, 5m/5 = 7/5 m = 7/5 简化并求解下列线性方程。 7. 3(t - 3) = 5(2t + 1) 答案: t = - 2 解释: 3(t - 3) = 5(2t + 1) 打开括号。 3t - 9 = 10t + 5 将 10t 移项到等号左边, 3t - 10t - 9 = 5 - 7t - 9 = 5 两边同时加上 9, - 7t - 9 + 9 = 5 + 9 - 7t + 0 = 14 - 7t = 14 两边同时除以 - 7, - 7t/-7 = 14/-7 t = - 14/7 t = - 2 8. 15(y - 4) -2(y - 9) + 5(y + 6) = 0 答案: y = 2/3 解释: 15(y - 4) -2(y - 9) + 5(y + 6) = 0 打开括号后的方程为, 15y - 60 - 2y + 18 + 5y + 30 = 0 15y - 2y + 5y - 60 + 18 + 30 = 0 18y - 12 = 0 两边同时加上 12, 18y - 12 + 12 = 0 + 12 18y + 0 = 12 18y = 12 两边同时除以 18, y = 12/18 y = 2/3 9. 3(5z - 7) - 2(9z - 11) = 4(8z - 13) - 17 答案: z = 2 解释: 3(5z - 7) - 2(9z - 11) = 4(8z - 13) - 17 打开括号后的方程为, 15z - 21 - 18z + 22 = 32z - 52 - 17 - 3z + 1 = 32z - 69 将 - 3z 移项到等号右边, 1 = 32z + 3z - 69 1 = 35z - 69 两边同时加上 69, 1 + 69 = 35z - 69 + 69 70 = 35z + 0 70 = 35z 两边同时除以 35, z = 70/35 z = 2 10. 0.25(4f - 3) = 0.05(10f - 9) 答案: f = 0.6 解释: 0.25(4f - 3) = 0.05(10f - 9) 打开括号后的方程为, f - 0.75 = 0.5f - 0.45 将 0.5z 移项到等号左边, f - 0.5 f - 0.75 = - 0.45 0.5f - 0.75 = - 0.45 两边同时加上 0.75, 0.5f - 0.75 + 0.75 = - 0.45 + 0.75 0.5f + 0 = 0.30 0.5f = 0.30 两边同时除以 0.5, 0.5f/0.5 = 0.30/0.5 f = 0.6 下一主题NCERT 八年级数学第三章 |
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